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3x^2-44x-484=0
a = 3; b = -44; c = -484;
Δ = b2-4ac
Δ = -442-4·3·(-484)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-88}{2*3}=\frac{-44}{6} =-7+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+88}{2*3}=\frac{132}{6} =22 $
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